) Find the value of 3 tan 12° cot 45° cot 60° tan 78º. 1
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(i) tan 12° cot 38° cot 52° cot 60° tan 78° = tan 12° cot 38° cot(90° – 38°) cot 60° tan(90° – 12°) = tan 12° cot 38° tan 38° cot 60° cot 12° [∵ cot(90° – θ) = tan θ] = tan12° x 1/tan12° x cot38° x 1/cot38° x cot60° = cot 60° = 1/√3Read more on Sarthaks.com - https://www.sarthaks.com/753212/find-the-value-of-the-following-i-tan-12-cot-38-cot-52-cot-60-tan-78
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