Question

find the value of 3 tan^2 A -3sec^2 A +3

Answer 1

⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐

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❄❄❄❄ SOLUTION ❄❄❄❄


3 tan²A - 3 sec²A + 3

= 3 (tan²A-sec²A) + 3

We know, sec²theta- tan²theta= 1
So - ( - sec²theta+tan²theta) = 1
=> tan²theta-sec²theta = -1

So, 3 (-1) + 3

= -3+3

= 0

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❄❄❄❄ REMEMBER ❄❄❄❄

1] sin²theta+cos²theta = 1

2] sec²theta-tan²theta = 1

3] cosec²theta-cot²theta = 1



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⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐

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Answer 2

3tan²A-3sec²A+3

=3(tan²A-sec²A)+3. (tan²-sec²=-1)
=3(-1) +3
=-3+3
=0