Question

Find the value of 3 tan square a minus 3 sec square a + 3

Answer 1

Answer:

3 tan²A-3 sec² A+3=3

3[tan²A-sec² A]=3-3

3[tan²A-sec² A]=0

[tan²A-sec² A]=0/3

[tan²A-1+tan² A]

[2tan²A-1]