Find the value of 3 tan square a minus 3 sec square a + 3
Answers
Answered by
1
Answer:
3 tan²A-3 sec² A+3=3
3[tan²A-sec² A]=3-3
3[tan²A-sec² A]=0
[tan²A-sec² A]=0/3
[tan²A-1+tan² A]
[2tan²A-1]
Similar questions