Find the value of 3 underroot 343 - 3 underroot 216
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Answered by
19
The answer is 1.
Explanation:
3 underroot 343= 7,
(343 can be written as 7³, cube root and 3 will be cancelled)
and 3 underroot 216 = 6
(216 can be written as 6³, cube root and 3 in the power of 6 will be cancelled)
so, 7-6 =1
Explanation:
3 underroot 343= 7,
(343 can be written as 7³, cube root and 3 will be cancelled)
and 3 underroot 216 = 6
(216 can be written as 6³, cube root and 3 in the power of 6 will be cancelled)
so, 7-6 =1
Answered by
28
Heya user !!
Here's the answer you are looking for
![\sqrt[3]{343} \: - \sqrt[3]{216} \\ = \sqrt[3]{ {7}^{3} } \: - \sqrt[3]{ {6}^{3} } \\ = 7 - 6 \\ = 1 \\ \\ \\ 343 = 7 \times 7 \times 7 = {7}^{3} \: \\ and \: 216 = 6 \times 6 \times 6 = {6}^{3}](https://tex.z-dn.net/?f=+%5Csqrt%5B3%5D%7B343%7D++%5C%3A++-++%5Csqrt%5B3%5D%7B216%7D++%5C%5C++%3D++%5Csqrt%5B3%5D%7B+%7B7%7D%5E%7B3%7D+%7D+++%5C%3A+-++%5Csqrt%5B3%5D%7B+%7B6%7D%5E%7B3%7D+%7D++%5C%5C++%3D+7+-+6++%5C%5C++%3D+1+%5C%5C++%5C%5C++%5C%5C+343+%3D+7+%5Ctimes+7+%5Ctimes+7+%3D++%7B7%7D%5E%7B3%7D+%5C%3A+++%5C%5C+and+%5C%3A+216+%3D+6+%5Ctimes+6+%5Ctimes+6+%3D++%7B6%7D%5E%7B3%7D+ "\sqrt[3]{343} \: - \sqrt[3]{216} \\ = \sqrt[3]{ {7}^{3} } \: - \sqrt[3]{ {6}^{3} } \\ = 7 - 6 \\ = 1 \\ \\ \\ 343 = 7 \times 7 \times 7 = {7}^{3} \: \\ and \: 216 = 6 \times 6 \times 6 = {6}^{3}")
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Here's the answer you are looking for
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