Question

find the value of (3°+4-¹)×2²

Answer 1

(1 + 1/4) × 4
=> (5/4) × 4
=> 5 = ans

hope this helps you..

Answer 2

Given,

The equation is given,

$(3^{0} + 4^{-1}) * 2^{2}$

To find,

Value of the equation

Solution,

Let's expand exponential parts and find value of each exponent first and then perform the operations.

$3^{0}$ is the first term, its in the form of $a^{0}$

Since, $a^{0} = 1$.

$3^{0} = 1$

$4^{-1}$ is the second term, its in the form of $a^{-1}$

Since, $a^{-1} = \frac{1}{a}$.

$4^{-1} = \frac{1}{4}$

$2^{2}$ is the second term,

$2^{2} = 2*2 = 4$

Now substitute these values and compute as given.

$(3^{0} + 4^{-1}) * 2^{2}$

= $( 1 + \frac{1}{4} ) * 4$

= $(\frac{5}{4})*4$

4 gets cancelled out and we will be left with 5

= 5

Hence, value of $(3^{0} + 4^{-1}) * 2^{2}$ is 5.