Find the value of (×)÷
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Given: A(a,3),B(2,1) and C(5,a) are collinear.
∴ Slope of AB= Slope of BC
⇒ 2−a1−3
= 5−2a−1
⇒ 2−a−2 = 3a−1
⇒−6=(2−a)(a−1)
⇒−6=2a−2−a 2 +a
⇒a 2 −3a−4=0
⇒a 2 −4a+a−4=0
⇒(a−4)(a+1)=0a=4,−1
For a=4 Slope of BC= 5−2a−1
= 34−1 = 33
=1Equation of BC;(y−1)=1(x−2)
⇒y−1=x−2
⇒x−y=1
For a=−1
Slope of BC= 5−2a−1
= 3−1−1
=− 32Equation of BC:(y−1)=− 32 (x−2)
⇒3y−3=4−2x
⇒2x+3y=7
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