find the value of !!
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Given equation is,
[cos(90°-∅)cos∅] / cot∅ - 1
we know that,
cos(90°-∅) = sin∅
sin∅cos∅/ (cos∅/sin∅) - 1
sin²∅ - 1 (:. cos∅ cancel out each other)
1- cos²∅ - 1
= - cos²∅
Hope this answer may help you
[cos(90°-∅)cos∅] / cot∅ - 1
we know that,
cos(90°-∅) = sin∅
sin∅cos∅/ (cos∅/sin∅) - 1
sin²∅ - 1 (:. cos∅ cancel out each other)
1- cos²∅ - 1
= - cos²∅
Hope this answer may help you
aman9340:
Hope it's help you
Answered by
3
[cos(90°-∅)cos∅] / cot∅ - 1
we know that,
cos(90°-∅) = sin∅
sin∅cos∅/ (cos∅/sin∅) - 1
sin²∅ - 1 (:. cos∅ cancel out each other)
1- cos²∅ - 1
= - cos²∅
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