Math, asked by manjubatti9, 4 days ago

find the value of 32√÷√2​

Answers

Answered by aftabahemad
1

In context to questions asked,

We have to determine the value of the given expression.

As per questions,

We have to determine the value of

 \sqrt{32}  \div  \sqrt{2}

As we know that,

 \sqrt{2}  \times  \sqrt{2}  = 2

Applying the above rule,

We can rewrite the expression given in question as,

 \sqrt{32}  =  \sqrt{2}  \times  \sqrt{16}

So, we will get,

 \frac{ \sqrt{2} \times  \sqrt{16}  }{ \sqrt{2} }  =  \sqrt{16}  =  \sqrt{ {4}^{2} }  = 4

Hence, value of the expression will be 4.

Actual Question,

Find the value of -

 \sqrt{32}  \div  \sqrt{2}

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