Math, asked by raj313442, 11 months ago

find the value of=32^2/5​

Answers

Answered by Anonymous
64

Answer:

 =  >  {32}^{ \frac{2}{5} }  \\  \\  =  >  {( {2}^{5}) }^{ \frac{2}{5} }  \\  \\  =  >  {2}^{5 \times  \frac{2}{5} }  \\  \\  =  >  {2}^{2 } \\  \\   =  > 4

Laws of Exponents:

 Product => {a}^{m} \times {a}^{n}= {a}^{m + n} \\ \\ Quotient => \frac{{a}^{m}}{{a}^{n}} = {a}^{m - n} \\ \\ Power => {({a}^{m})}^{n} = {a}^{m \times n} \\ \\ Inverse => {a}^{-1} = \frac{1}{a} \\ \\ Zero \: Power => {a}^{0} = 1

Answered by PrakritiMinTae
3

Step-by-step explanation:

35^2/7

(7*5)^2/5

7^2 *5^2/5

49*5

245

hope this helps

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