Question

find the value of 3²÷3​

Answer 1

Answer:

By using,

{ ({a}^{m} )}^{n} = {a}^{mn}(a

m

)

n

=a

mn

We get,

{ ({3}^{2}) }^{3} = {3}^{2 \times 3}(3

2

)

3

=3

2×3

= {3}^{6}=3

6

= 729

Answer 2

Answer:

$\sf \: The \: value \: of \sqrt{3}^{-2}=\dfrac{1}{3}$

We have,

$\sqrt{3}^{-2}$

$To \: find, \: the \: value \: of \sqrt{3}^{-2}=?$

$∴ \sqrt{3}^{-2}$

$=\dfrac{1}{\sqrt{3}^{2}}$

$a^{-m} =\dfrac{1}{a^{m}}$

$=\dfrac{1}{\sqrt{3}\times \sqrt{3}}=$

$=\dfrac{1}{3}$

$∵ \sqrt{3} \times\sqrt{3}=3$

$\sf∴The \: value \: of \sqrt{3}^{-2}=\dfrac{1}{3}$

$\sf \: Thus, the \: value \: of \sqrt{3}^{-2}=\dfrac{1}{3}$