find the value of√32+√48/√8+√12
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√32 + √48 /√8 + √12
√4*√8 + √4*√12/√8+√12 (√4*√8=√32,√4 * √12 = √48)
2√8 + 2√12/√8+√12 ( √4=2 )
2(√8+√12)/1(√8+√12) ( 2 taken common and 1 taken common)
ans = 2/1= 2 (√8+√12 cancelled out)
√4*√8 + √4*√12/√8+√12 (√4*√8=√32,√4 * √12 = √48)
2√8 + 2√12/√8+√12 ( √4=2 )
2(√8+√12)/1(√8+√12) ( 2 taken common and 1 taken common)
ans = 2/1= 2 (√8+√12 cancelled out)
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