Find the value of:
(32)-⅔ ÷ (64)-⅔
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IDENTITY 1=> aⁿ ÷ bⁿ =[a ÷ b]-
[32/64]-⅔
IDENTITY 2=> [a]⁻ᵇ = [1/a]ᵇ
{1 ÷ (32/64)} ⅔ {RECIPROCAL THE 2ND TERM}
{1×64/32}
2⅔
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