Question

Find the value of: 345 × 91 + 9 × 345​

Answer 1

Answer:

rule of 2, 3, 4, 5, and then test each of them.

So, for the divisibility rule of 2 if the number is even or a number whose last digit is an even number that is 2, 4, 6, 8 including 0 it is always divisible by 2.

For example, let's say 508, its last digit is 8 which is even and divisible by 2. So, it is divisible by 2.

Thus for 345, its last digit is 5 so, as it is odd thus it is not divisible by 2.

For the divisibility rule of 3 if the sum of digit of the number is divisible by 3 then the number itself will be divisible by 3.

For example, let's say 123, its sum of digit is (1+2+3)⇒6(1+2+3)⇒6, which is divisible by 3, hence the number 123 is divisible by 3.

Thus, for 345 its sum of digit is (3+4+5)⇒12(3+4+5)⇒12, which is divisible by 3. Thus, 345 is divisible by 3.

For the divisibility rule of 4, check for the last two digits of the number. If they are divisible by 4 then the number is divisible by 4.

For example, let’s say 108 its last 2 digits is 08, which is divisible by 4 thus the number is divisible by 4.

Thus, for 345 its last 2 digits are 45 which is not divisible by 4. Thus, the number is not divisible by 4.

For the divisibility rule of 5, the last number should be either 0 or 5 then it will be divisible by 5.

For example, let's say 125, its last digit is 5. Thus, it is divisible by 5.

Thus, for 345 its last digit is 5, hence it will be divisible by 5.