Question

Find the value of (3⁷+4‐³+5³)⁰​

Answer 1

Answer:

(3⁷+4‐³+5³)⁰

= 0

Step-by-step explanation:

Something to the power 0 = 1

But,

$0^0\neq1$

so general form,

$x^0\:=\:1\:\:where\:x\neq0$