Question

Find the value of 3ab+2bc+ac, for a=1,b=(-1),c=0.​

Answer 1

Answer:

3ab+2bc+ac

On putting a=1,b=(-1),c=0

3(1)(-1)+2(-1)(0)+1*0

3*(-1)+2*0+0

-3+0+0

-3

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Answer 2

Answer:

=3ab+2bc+ac

3(1)(-1)+2(-1)(0)+(-1)(0)

-3+0+0

Ans=-3

Step-by-step explanation:

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