Find the value of 3ab+2bc+ac, for a=1,b=(-1),c=0.
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Answered by
4
Answer:
3ab+2bc+ac
On putting a=1,b=(-1),c=0
3(1)(-1)+2(-1)(0)+1*0
3*(-1)+2*0+0
-3+0+0
-3
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Answered by
0
Answer:
=3ab+2bc+ac
3(1)(-1)+2(-1)(0)+(-1)(0)
-3+0+0
Ans=-3
Step-by-step explanation:
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