Find the value of- 3log3^81
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Step-by-step explanation:
We have,
log
2
(log
3
81)
=log
2
(log
3
3
4
)
=log
2
(4log
3
3)[∵log
a
x
n
=nlog
a
x]
=log
2
4[∵log
a
a=1]
=log
2
2
2
=2log
2
2
=2×1
=2
Hence, this is the answer.
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