Question

Find the value of (3p^2 +4q-r) x pqr, if p = 1,q = 2 and r = 3.​

Answer 1

Answer:

48

Step-by-step explanation:

Substitute all the values in respective places :

$=(3(1)^{2}+4(2)-3)×1×2×3$

$=(3+8-3)×6$

$=(8)×6$

$=48$

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