Math, asked by nk0914315, 4 days ago

Find the value of 3p²-8pq when p =-2 and q = 1. a. C. 20 40 b. d. 28 30​

Answers

Answered by RehanKhan08
2

Answer:

3p^2 - 8pq when p= -2 and q= 1

solution : 3(-2)^2 - 8(-2)(1)

square of negative number is always

positive

therefore 3(4) + 16

12 + 16

= 28

Step-by-step explanation:

Hope this helped you :(

Answered by mamtamaurya9696
0

Answer:

-4 is the answer

Step-by-step explanation:

3p²-8pq

3(-2×-2)-8(-2×1)

3×4-8×2

12-16

-4

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