Math, asked by nethrandevi, 11 months ago

find the value of 3sin2 20degree- 2tan2 45degree+3 sin2 70degree

Answers

Answered by Anonymous
11

hi dude

Answer:

Step-by-step explanation:

3sin²20°-2tan²45°+3sin²70°

=3sin²20°-2×(tan45°)²+3{sin(90°×1)-20°}²

=3sin²20°-2×(1)²+3cos²20°

=3(sin²20°+cos²20°)-2

=3-2 [∵, sin²20°+cos²20°=1]

=1 Ans.

hope it helps u!!!

Answered by piyushkumar22
8
3sin²20°-2tan²45°+3sin²70°
=3sin²20°-2×(tan45°)²+3{sin(90°×1)-20°}²
=3sin²20°-2×(1)²+3cos²20°
=3(sin²20°+cos²20°)-2
=3-2 [∵, sin²20°+cos²20°=1]
=1 Ans.




nethrandevi: its wrong
nethrandevi: no
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