Math, asked by deveshpatel0922, 1 year ago

find the value of ''3tan^2A-3sec^2A+3''

Answers

Answered by mysticd
5
Solution :

3tan²A - 3sec²A + 3

= 3( tan²A - sec²A ) + 3

= 3 ( -1 ) + 3

************************************
We know the Trigonometric identity:

1 + tan²A = sec²A

=> tan²A - sec²A = -1
***********************************

= -3 + 3

= 0

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