find the value of 3tan²26° – 3cosec²64°
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Hey there!!
Here's your answer..
3 cosec² 64° can be written as 3 sec² (90° - 64°) which is 3 sec² (26°)
Because, sec (90° - α) = cosec (α)
As asked, we are required to find 3 tan² 26° – 3 cosec² 64°
Which is equal to 3 tan² 26° - 3 sec² 26° = 3 ( tan² 26° - sec² 26°)
We know that sec² α - tan² α = 1 ⇒ tan² α - sec² α = - 1
So, 3 ( tan² 26° - sec² 26°) = 3 ( - 1) = - 3
So, the value of 3 tan² 26° – 3 cosec² 64° is equal to - 3
Hope it helped you!!
Here's your answer..
3 cosec² 64° can be written as 3 sec² (90° - 64°) which is 3 sec² (26°)
Because, sec (90° - α) = cosec (α)
As asked, we are required to find 3 tan² 26° – 3 cosec² 64°
Which is equal to 3 tan² 26° - 3 sec² 26° = 3 ( tan² 26° - sec² 26°)
We know that sec² α - tan² α = 1 ⇒ tan² α - sec² α = - 1
So, 3 ( tan² 26° - sec² 26°) = 3 ( - 1) = - 3
So, the value of 3 tan² 26° – 3 cosec² 64° is equal to - 3
Hope it helped you!!
pranjlshrm:
thnxx
suno aapne sec²a - tan²a = 1 ko tan²a - sec²a = -1 kese kiya????
plss jaldi batao
Multiply with -1 on both sides, you will get the required
ooo okk
thnxx
but u havent ryt - in LHS
when you multiply with - sign, lhs becomes - sec^2 (a) + tan ^2 (a) which is nothing but tan ^2 (a) - sec^2 (a)
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