Find the value of 3tan26°-3cosec64°
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tan(26°)=cot(90-26) = cot(64°)
so 3tan^2(26)=3cot^2(64)
so 3tan^2(26)–3cosec^2(64) can be written as
3cot^2(64)–3cosec^2(64)
= 3[cot^2(64)–cosec^2(64)] = 3(-1) = -3
Cheers. Mark brainliest.
so 3tan^2(26)=3cot^2(64)
so 3tan^2(26)–3cosec^2(64) can be written as
3cot^2(64)–3cosec^2(64)
= 3[cot^2(64)–cosec^2(64)] = 3(-1) = -3
Cheers. Mark brainliest.
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Hope so its right. Not sure
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