find the value of√3tan30°+√2sin45°+2/√3sin60°-cot40°
sreeramjvp:
dude is it divison '√3tan30°+√2sin45°+2' after this??
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√3 tan 30=√3×1/√3=1
√2sin30=√2×1/√2=1
2/√3sin60=2/√3×2/√3=4/3
cot40=1
1+1+4/3-1=7/3
√2sin30=√2×1/√2=1
2/√3sin60=2/√3×2/√3=4/3
cot40=1
1+1+4/3-1=7/3
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√3*1\√3+√2*1+2\√3*√3\2-cot40
1 +√2+1
2+√2
Thank you very much
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