find the value of:
(3tan41/cot49)^2 - (sin35sec55/tan10tan20tan60tan70tan80)^2
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1
Answer:
8.67
Step-by-step explanation:
(3tan41/cot49)^2 =9
(sin35sec55/tan10tan20tan60tan70tan80)^2 = .33
3-.33 = 8.67
pankhudirajsingh:
Can u explain how did t get that .33 and 3 plz
sin35 =.574, sec55 =1.74, tan10 =.176, tan20 =.364, tan60 =1.732, tan70 =2.747, tan80 =5.671.
tan41 =.869, cot49 =.869
i write all the value , now u easily solve your question.
Thans mohit for ur really kind gesture ;-):-):-D
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