find the value of (3x+2y)²
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Answer:
9x^2+4y^2+12xy
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Answer:
The value of (3x + 2y) ^2 is 9x^2 + 12xy + 4y^2
Step-by-step explanation:
(a + b) ^2 = a^2 + 2ab + b^2
(a + b) ^2 = a^2 + 2ab + b^2(3x + 2y) ^2 = (3x) ^2 + 2 * 3x * 2y + (2y) ^2
(a + b) ^2 = a^2 + 2ab + b^2(3x + 2y) ^2 = (3x) ^2 + 2 * 3x * 2y + (2y) ^2= 9x^2 + 12xy + 4y^2
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