Question

Find the value of 3x(2y+3z) if x=-1,y=2 and z=-2

Answer 1

Answer:

$given \: \: \: 3x(2y + 3z) =$

$x = - 1 \: y = 2 \: z = - 2$

$then \: 3( - 1)(2 \times 2 + 3 \times - 2)$

$= ( - 3)(4 - 6)$

$- 3 \times - 2$

$= > 6$

Answer 2

Step-by-step explanation:

3x(2y+3z)

3x(2y+3z)=3×-1(2×2+3×-2)

3x(2y+3z)=3×-1(2×2+3×-2)={-3[4+(-6)]}

3x(2y+3z)=3×-1(2×2+3×-2)={-3[4+(-6)]}=[-3(4-6)]

=6

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