Question

find the value of (3x^3) × (-5xy^2) ×(2x^2yz^3) for x=1, y= 2 and z=3.​

Answer 1

Answer:

answered May 17, 2019 by muskan15 (-3,443 points)

For x = 1, y = 2 and z = 3

(3x3) × (-5xy2) × (2x2yz3)

(3 × 13) × (-5 × 1 × 22) × (2 × 12 × 2 × 33)

3 × (-5 × 4) × (2 × 1 × 2 × 27)

3 × (-20) × 108 = -6480

Step-by-step explanation: