find the value of 3x+3y if x+y=20and x-y=-4.
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Answer:
Method 1: If (x+y) = 20
Then,
= 3x+3y
= 3(x+y)
= 3(20)
= 60
Method 2: Given,
(x+y) = 20 ....(i)
(x-y) = -4 ....(ii)
Substituting the value of x from eq i,
x = 20-y
Value of y from eq ii,
= 20-y-y = -4
= 20-2y = -4
= 24 = 2y
= y = 12
Value of x = (x+12) = 20
= x = 8
= 3x+3y
= 3*8 + 3*12
= 24+36
= 60
Hope this helps.
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