Question

Find the value of 3x2 + 2y2 – 2 for x = 3 and y = 1.​

Answer 1

$\huge \sf \underbrace {Given}$

$\sf \implies \:x = 3 \: and \: y = 1$

$\huge \sf \underbrace{To \: Find}$

$\sf \: the \: value \: of \: 3x2 + 2y2 – 2$

$\huge \sf \underbrace{Answer}$

Let's put the given values:-

$\sf \implies3 \times 3 \times 2 + 2 \times 1 \times 2 - 2$

$\sf \implies9 \times 2 + 4 - 1$

$\sf \implies18 + 2 - 2$

$\sf \implies20 - 2$

$\implies \sf \fbox \pink{18}$

Therefore the value of 3x2 + 2y2 – 2 is 18

Answer 2

Let's put the given values:- of x and y in the equation 3x2 + 2y2 – 2

$\sf \implies3 \times 3 \times 2 + 2 \times 1 \times 2 - 2⟹3×3×2+2×1×2−2$

$\sf \implies9 \times 2 + 4 - 1⟹9×2+4−1$

$\sf \implies18 + 2 - 2⟹18+2−2$

$\sf \implies20 - 2⟹20−2$

$\implies \sf \fbox \orange{18}$

Therefore the value of 3x2 + 2y2 – 2 is 18