Math, asked by archanasinghanil79, 1 day ago

Find the value of 3xy when x = 1, y= –2 a. 6 b. 2 c. –6 d. –2

Answers

Answered by HEARTLESSBANDI
1

Step-by-step explanation:

Find the value of 3xy when x = 1, y= –2

a. 6

Given, x = 6, y = 2

To solve for 3xy + 2x^2y^3 3xy + 2x^2y^3 xy ( 3 + 2xy^2 ) 6 × 2 ( 3 + 2 × 6 (2)^2 ) 12 ( 3 + 48 ) 12 × 51 612=619,344

Answered by Anonymous
1

Answer:

Find the value of 3xy when x = 1, y=-2

a. 6

Given, x = 6, y = 2

To solve for 3xy + 2x^2y^3 3xy + 2x^2y^3 xy (3 + 2xy^2) 6 × 2 (3 +2×6 (2)^2 ) 12 (3 + 48) 12 x 51 612-619,344

Step-by-step explanation:

i hope it helps you ☺️ ☺️ ✌️

have a nice day ☺️

Similar questions