Question

Find the value of ( 4^0+4^-1)*2^2​

Answer 1

(4^0 + 4^-1)*2^2

(1+1/4)*4

((4+1)/4)*4

4+1

5

Answer 2

$\displaystyle \sf{ ( {4}^{0} + {4}^{ - 1} ) \times {2}^{2} } = 5$

Given :

$\displaystyle \sf{ ( {4}^{0} + {4}^{ - 1} ) \times {2}^{2} }$

To find :

The value of the expression

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

$\displaystyle \sf{ ( {4}^{0} + {4}^{ - 1} ) \times {2}^{2} }$

Step 2 of 2 :

Find the value of the expression

$\displaystyle \sf{ ( {4}^{0} + {4}^{ - 1} ) \times {2}^{2} }$

$\displaystyle \sf{ = \bigg( 1 + \frac{1}{4} \bigg) \times 4 }$

$\displaystyle \sf{ = (1 \times 4) + \bigg( \frac{1}{4} \times 4 \bigg) }$

$\displaystyle \sf{ = 4 + 1 }$

$\displaystyle \sf{ = 5 }$

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