Math, asked by ushajain8523, 8 months ago

find the value of 4√16^-2​

Answers

Answered by sehrawatsahil570
11

Answer:

the answer is 4^-1.

Step-by-step explanation:

  • 4(16)^(1/2×-2)
  • 4(4)^2×-1
  • 4^-1
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Answered by pulakmath007
1

\displaystyle \sf   \sqrt[4]{ {16}^{ - 2} }  = \bf  \frac{1}{4}

Given :

\displaystyle \sf   \sqrt[4]{ {16}^{ - 2} }

To find :

The value of the expression

Solution :

Step 1 of 2 :

Write down the given expression

Here the given expression is

\displaystyle \sf   \sqrt[4]{ {16}^{ - 2} }

Step 2 of 2 :

Find the value of the expression

\displaystyle \sf   \sqrt[4]{ {16}^{ - 2} }

\displaystyle \sf   =  \sqrt[4]{  \frac{1}{ {16}^{2} }  }

\displaystyle \sf   =  \sqrt[4]{  \frac{1}{ 16 \times 16 }  }

\displaystyle \sf   =  \sqrt[4]{  \frac{1}{ (2 \times 2 \times 2 \times 2) \times (2 \times 2 \times 2 \times 2) }  }

\displaystyle \sf   =  \sqrt[4]{  \frac{1}{  {2}^{4}  \times  {2}^{4}  }  }

\displaystyle \sf   =  \sqrt[4]{  \frac{1}{  {(2 \times 2)}^{4}   }  }

\displaystyle \sf   =  \sqrt[4]{  \frac{1}{  {4}^{4}   }  }

\displaystyle \sf   =  {\bigg( \frac{1}{ {4}^{4} } \bigg)}^{ \frac{1}{4} }

\displaystyle \sf   =  \frac{1}{4}

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