Question

Find the value of 4/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵

Answer 1

Answer:

4-4--4-4--3-3&3&33+3+3+3+3((3(3(3(2(2(2(

Explanation:

7272+3+2+$+$-3-3+3+$2(2((3+2+$($4+3

Answer 2

4/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵ = 214

Explanation:

4/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵

Taking one term at a time, we solve as follows:

4/ (216)⁻²/³ = 4 / (216)⁻²/³ = 4 * 216²/³ = 4 * (6³)²/³ = 4 * 6² = 144

1/ (256)⁻³/⁴ = (256)³/⁴ = (4⁴)³/⁴ = 4³ = 64

2/(243)⁻¹/⁵ = 2 * (243)¹/⁵ = 2 * (3⁵)¹/⁵  = 2 * 3 = 6

4/(216)⁻²/³ + 1/(256)⁻³/⁴ + 2/(243)⁻¹/⁵ = 144 + 64 + 6 = 214