Math, asked by roseglair22, 10 months ago

find the value of 4/(216)‐²/³ + 1/(256)‐³/⁴ + 2/(243)‐¹/⁵ plsssss solve i will die​

Answers

Answered by SamithSurya
2

Step-by-step explanation:

4/(6^3)^-2/3+1/(4^4)^-3/4+2/(3^5)^-1/5

(a^m)^n=a^mn

4/6^-2+1/4^-3+2/3^-1

4/1/36+1/1/64+2/1/3

4×36+1×64+2×3

144+64+6

214

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