Question

find the value of (4⁰+4-¹) × 2²​

Answer 1

Answer:

(4^0+4^-1) ×2^2

(1+1/4) ×4

5/4×4

5

Step-by-step explanation:

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Answer 2

Answer:

5 is the required value of  (4⁰+4-¹) × 2²​

Step-by-step explanation:

Explanation:

Step 1:

We have, ($4^0+ 4^{-1}$)× $2^2$

⇒ (1 + $\frac{1}{4}$) × $2^2$

LCM of 4 and 1 is 4

⇒$(\frac{4+1}{4}) .(2)^2$ = $\frac{5}{2^2} (2^2)$ = 5

Final answer:

Hence, 5 is the required answer

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