Math, asked by sstabya, 6 months ago

find the value of 4√(81)^2​

Answers

Answered by BibekKumarRoyBarman
0

Answer:

324

 (\sqrt{4 \times 4 \times 81) }^{2}

 { \sqrt{16 \times 81} }^{2}

 { \sqrt{324} }^{2}

324

Answered by Salmonpanna2022
0

Step-by-step explanation:

 \bf \underline{Solution-} \\

 \bf{ \sqrt[4]{(81 {)}^{ - 2} }  }\\

 \bf =   \sqrt[4]{ \bigg( \frac{1}{81} \bigg) ^{2}  }  \\

  \bf =  \sqrt[4] {\left\{{ \bigg( \frac{1}{9}  \bigg) ^{2} }\right\} ^{2} } \\

 \bf =  \sqrt[4]{ \bigg( \frac{1}{9}  \bigg) ^{4} }  \\

 \bf  =  \bigg( \frac{1}{9}  \bigg) ^{4 \times  \frac{1}{4} }  \\

 \bf =  \frac{1}{9}  \: \\

 \bf \underline{Hence \:  the  \: value  \: of \:  \sqrt[4]{(81 {)}^{ - 2}  } } \: is \:  \frac{1}{9} . \\

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