Math, asked by Mishrji, 1 year ago

find the value of 4 root 3-3ROOT12 +2 root 75

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Answered by mayank2004raj
138

4 \sqrt{3}  - 3 \sqrt{12}  + 2 \sqrt{75}  \\  = 4 \sqrt{3}  - 3 \sqrt{2 \times 2 \times 3}  + 2 \sqrt{5 \times 5 \times 3}  \\  = 4 \sqrt{3}  - 6 \sqrt{3}  + 10 \sqrt{3}  \\  = 8 \sqrt{3}  \\  \\ hope \: it \: helped \: you \: have \: a \: wonerful \: day \: ahead

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Answered by shraiyakheria2006
17

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