Question

find the value of 4 root 3 minus 3 root 12 + 2 root 75​

Answer 1

Step-by-step explanation:

$4 \sqrt{3} - 3 \sqrt{12} + 2 \sqrt{75} \\ = 4 \sqrt{3} - 3 \sqrt{4 \times 3} + 2 \sqrt{25 \times 3} \\ = 4 \sqrt{3} - 3( \sqrt{4} \times \sqrt{3} ) + 2( \sqrt{25} \times \sqrt{3} ) \\ = 4 \sqrt{3} - 6 \sqrt{3} + 10 \sqrt{3} \\ = \sqrt{3} (4 + 10 - 6) \\ = \sqrt{3} (14 - 6) \\ = 8 \sqrt{3}$

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