Question

find the value of 4 tan 45 + 3 Cos 60 + 3 sin square 60 + tan30 cot 45​

Answer 1

Answe

Step-by-step explanation:see below photo for answer. Give it the brainiest answer please

Answer 2

$4\tan 45+3\cos 60+3\sin^2 60+\tan 30\cot 45=\frac{30\sqrt{3}+4}{4\sqrt3}$

Step-by-step explanation:

Given : Expression $4\tan 45+3\cos 60+3\sin^2 60+\tan 30\cot 45$

To find : The value of expression ?

Solution :

Expression $4\tan 45+3\cos 60+3\sin^2 60+\tan 30\cot 45$

Using trigonometric values,

$\sin 60=\frac{\sqrt3}{2}$

$\cos 60=\frac{1}{2}$

$\tan 30=\frac{1}{\sqrt3}$

$\tan 45=1$

$\cot 45=1$

Substitute the values,

$=4(1)+3(\frac{1}{2})+3(\frac{\sqrt3}{2})^2+(\frac{1}{\sqrt3})(1)$

$=4+\frac{3}{2}+\frac{9}{4}+\frac{1}{\sqrt3}$

$=\frac{15\sqrt{3}+6\sqrt{3}+9\sqrt{3}+4}{4\sqrt3}$

$=\frac{30\sqrt{3}+4}{4\sqrt3}$

Therefore, $4\tan 45+3\cos 60+3\sin^2 60+\tan 30\cot 45=\frac{30\sqrt{3}+4}{4\sqrt3}$

#Learn more

sin 30 cos 30 + cos 30 sin 60 = sin 90​

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