Question

Find the value of 41 upon 3 minus 2 upon 9

Answer 1

$\frac{41}{3} - \frac{2}{9}$

$\frac{41}{3} \times 9 - \frac{2}{9} \times 9$

$\frac{41 \times 3}{9} - \frac{2}{9}$

$\frac{123 - 2}{9}$

$\frac{121}{9}$