Question

Find the value of 4⁵ x 2³ x 2-⁶ in exponents.​

Answer 1

Answer:

${4}^{5} \times {2}^{3} \times {2}^{ - 6} \\ {2}^{10} \times {2}^{3} \times {2}^{ - 6} \\ {2}^{10 + 3 - 6} \\ {2}^{7}$

Hope my answer helps.

Answer 2

Given:

4⁵ x 2³ x $2^{-6}$

To Find:

The value of 4⁵ x 2³ x  $2^{-6}$ in exponents.​

Solution:

Here we will use the exponents' rule for simplifying the given exponents

Product of powers rule:

''When multiplying two bases of the same value, keep the bases the same and then add the exponents together to get the solution''.

we can see that the base of  2³ x $2^{-6}$  is the same.

So we will make the base of  4⁵ in accordance with the other two.

4⁵ = $(2^{2}) ^{5}$      (∴ 4 = 2²)

4⁵ = $2^{10}$

Now we will solve the exponents using  $2^{10}$ in place of 4⁵

According to the question:

4⁵ x 2³ x  $2^{-6}$ =  $2^{10}$ x 2³ x  $2^{-6}$

4⁵ x 2³ x  $2^{-6}$ = $2^{(10+3-6)}$              (∴ Base is same ∵ power gets add)

4⁵ x 2³ x  $2^{-6}$ = $2^{7}$

Hence,  the value of  4⁵ x 2³ x  $2^{-6}$  in exponents is  $2^{7}$