Question

find the Value of (4⁷ + 4-³ + 7³)⁰​

Answer 1

Answer:

answer is 1 because the power of whole no. is 0

Answer 2

Answer:

$(4^7 + 4^{-3} + 7^3)^0$ = 1

Step-by-step explanation:

given that :

we have to find the value of $(4^7 + 4^{-3} + 7^3)^0$

$4^7$ = (4)(4)(4)(4)(4)(4)(4)

let's multiply the above in small packets

= (16)(16)(16)(4)

= (256)(64)

=16384

$4^{-3}$ = (1/4)(1/4)(1/4)

= (1/16)(1/4)

= (1/64)

$7^3$ = (7)(7)(7)

= (49)(7)

= (343)

value of $(4^7 + 4^{-3} + 7^3)^0$  is :

substitute values of  $4^7$ , $4^{-3}$ , $7^3$ in above problem:

$(4^7 + 4^{-3} + 7^3)^0$ = (16384 + (1/64) + 343)⁰

= (16384  + 343 + (1/64))⁰

= [16727 + (1/64)]⁰

= [ (64)(16727 ) + (1) ]⁰/ (64)⁰

= [1070528 + 1]⁰/(64)⁰

= (1070529/64)⁰

= (16727.015)⁰

we know that anything power '0' is 1

so   (16727.015)⁰  = 1

$(4^7 + 4^{-3} + 7^3)^0$ = 1