Question

find the value of (49x2+36y2)if (7x+6y)=√2and xy=√5.

Answer 1

${49x}^{2} + {36y}^{2} \\ ( {7x)}^{2} + ( {6y)}^{2} + 42xy - 42xy \\ {(7x + 6y)}^{2} - 42xy \\ {( \sqrt{2)} }^{2} - 42( \sqrt{5} ) \\ 2 - 42 \sqrt{5}$
Here is your answer...

2-42√5

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