Question

find the value of (4i)×(-6i)
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Answer 1

$\large\bf\red{ \diamond} \rm \: \: (4i) \: \times \: ( - 6i) \\ \\ \large\bf\red{ \diamond} \rm \: \: - 24 \: {i}^{2}$

Answer 2

Answer:

!! Hey Mate !!

your answer is --

Let, A = 4i^ and B = (-6k^)

we can write it as

A = 4i^ + 0j^ + 0k^ and

B = 0i^ +0j^ - 6k^

such that , a1 = 4 , a2=0, a3=0 and

b1 = 0 , b2 = 0 , b3= -6

we know that ,

A × B = i^(a2b3-b2a3) - j^(a1b3-b1a3) +k^(a1b2-b1a2)

=> A×B = i^(0×-6-0×4)-j^(4×-6-0×0)+k^(4×0-0×0)

=> A×B = i^(0) - j^(-24) +k^(0)

=> A×B = 24j^

Explanation: