Math, asked by Anonymous, 1 year ago

Find the value of 4sin50° - √3tan50°

Answers

Answered by abhi178

4sin50° - √3tan50°

= 4sin50° - √3sin50°/cos50°

= ( 4sin50.cos50° - √3sin50°)/cos50°

use formula ,
2sinAcosA = sin2A

= { 2sin100° - √3sin50° }/cos50°

= 2{ sin(180°-80°) - √3/2 sin50°}/cos50°

= 2{ sin80° - cos30°.sin50°}cos50°

= 2{ sin80° -1/2(2sin50°.cos30°)}cos50°

use formula ,
2sinA.cosB = sin( A+B)+sin(A - B)

= 2{ sin80° -1/2( sin80° + sin20°)}/cos50°

= 2{ 1/2sin80° - 1/2sin20°}/cos50°

= ( sin80° - sin20°)/cos50°

use formula ,
sinA - sinB = 2cos( A + B)/2.sin(A - B)/2

={2cos( 80+20)/2.sin(80-20)/2 }/cos50°

= 2cos50° .sin30°/cos50°

= 2sin30°

= 2 × 1/2 = 1

Anonymous: 2sinAcosB ≠ sin(A+B) + sin(A-B)

abhi178: read fromula ,

abhi178: what are doing you don't know this

abhi178: its a basic formula ,

Anonymous: oh sorry i confused it with sin2A thanks a lot

abhi178: its okay , first read , think then say right or wrong . xD

Anonymous: I'm sorry

abhi178: its okay no problem , any doubt you send in my inbox

abhi178: thank you

Anonymous: ok thank you for ur kind gesture

Answered by depanjanghosh73

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