Math, asked by mahuvawalazahra, 6 months ago

Find the value of
4x^2+3 , when x = -5​

Answers

Answered by kapatil044
1

Answer:

substituting x = -5 in equation 4x²+3=0

= 4×(-5)²+3

= 4×25+3

= 100+3

= 103

Answered by 2008shrishti
2

Answer:

Answer:

substituting x = -5 in equation 4x²+3=0

= 4×(-5)²+3

= 4×25+3

= 100+3

= 103

Step-by-step explanation:

Hope this answer will help you.

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