find the value of 4x^2+9y^2 if 2x+3y=18and xy=5
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Solution:
Given that,
2x+3y = 18 & xy = 5
∴ 4x²+9y²
= (2x)²+(3y)²
= (2x+3y)²-2·2x·3y
= (2x+3y)²-12xy
=18²-12×5
= 324-60
= 264
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