find the value of (4x+5y)^2-(4x-5y)^2
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Answer:
Just multiply it out:
(4x+5y)2 - (4x-5y)2
= 16x2 + 40xy + 25y2 - (16x2 - 40xy + 25y2)
= 80xy
You can also solve it using the difference of squares formula:
a2 - b2 = (a-b)(a+b)
Where a=4x+5y and b=4x-5y
(4x+5y-4x+5y)(4x+5y+4x-5y)
(10y)(8x) = 80xy
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