Math, asked by AditiRath869, 10 months ago

Find the value of 4x²+y²+25z²+4xy-10yz-20zx when x = 4, y = 3 and z = 2.

Answers

Answered by nikitasingh79
10

Given : 4x² + y² + 25z² + 4xy - 10yz - 20zx

=  (2x)² + (y)² + (- 5z)² + 2x × 2y + 2 × y × -5z + 2 × -5z × 2x

= (2x + y - 5z)²

Given : x = 4, y = 3 and z = 2

= (2 × 4 + 3 - 5 × 2)²

= (8 + 3 - 10)²

= (11 - 10)²

= (- 1)²

= 1

Hence, the value of 4x² + y² + 25z² + 4xy - 10yz - 20zx is 1.

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Answered by Anonymous
2

Answer:

Step-by-step explanation:

= (2 × 4 + 3 - 5 × 2)²

= (8 + 3 - 10)²

= (11 - 10)²

= (- 1)²

= 1

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