Question

Find the value of -4x²y²+2xy³-3x²y when x= -2, y=3​

Answer 1

Answer:

-288

Step-by-step explanation:

x = -2, y = 3​

-4x²y² + 2xy³ - 3x²y = -4*-2²*3² + 2*-2*3³ - 3*-2²*3

= -4*4*9 + 2*-2*27 - 3*4*3

= -144 - 108 - 36

= -288